3w^2+7w=7

Solution for 3w^2+7w=7 equation:

3w^2+7w=7

We move all terms to the left:

3w^2+7w-(7)=0

a = 3; b = 7; c = -7;
Δ = b2-4ac
Δ = 72-4·3·(-7)
Δ = 133
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{133}}{2*3}=\frac{-7-\sqrt{133}}{6}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{133}}{2*3}=\frac{-7+\sqrt{133}}{6}
$